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5x^2-16x-2484=0
a = 5; b = -16; c = -2484;
Δ = b2-4ac
Δ = -162-4·5·(-2484)
Δ = 49936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{49936}=\sqrt{16*3121}=\sqrt{16}*\sqrt{3121}=4\sqrt{3121}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{3121}}{2*5}=\frac{16-4\sqrt{3121}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{3121}}{2*5}=\frac{16+4\sqrt{3121}}{10} $
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